`f(x)={(e^x-1)/(log(1+2x)),\ \ \ if\ x!=0\ \ \ \ \ \ \ \ \ 7,\ \ \ \ \ \ \ \ \ \ \ if\ x=0` at `x=0`

Find the points of discontinuity, if any, of the following function: f(x)={(e^x-1)/((log)_e(1+2x))\ \ \ ,\ \ \ if\ x!=0\ \ \ \ \ 7\ \ \ ,\ \ \ if\ x=0

'f(x)={(e^(^^)x-1)/(log(1+2x)),|x!=0Kx=0at

f(x)={(e^(x)-1)/(log(1+2x)),, if x!=0quad 7,quad if x=0 at x=0

f(x)={(log(1+2ax)-log(1-bx))/(x),x!=0x=0

f(x) {:( =((2^(x)-1)^(2))/(sin x.log(1+x))", if " x != 0 ),(= 2 log 2", if " x = 0 " ) :} , at x = 0 the function f is

If f(x) {:( =((2^(x)-1)^(2))/(sin x.log(1+x))", if " x != 0 ),(= 2 log 2", if " x = 0 " ) :} then , at x = 0 the function f is

If f(x)=(e^(2x)-(1+4x)^(1/2))/(ln(1-x^(2))) for x!=0, then f has

If f(x) = log_e ((1-x)/(1+x)) , then f' (0) is

if f(x)=e^(-(1)/(x^(2))),x>0 and f(x)=0,x<=0 then f(x) is

If f(x)={:{((e^(1/x)-1)/(e^(1/x)+1)", for " x !=0),(1", for " x=0):} , then f is