If `x sin 60^@ cos^@ 30^@ = (tan^2 45^@ sec 60^@)/("cosec 60"^@)` then find the value of x.

Solve: x tan 60^@cos^2 30^@ = (tan^2 45^@ sec 60^@)/(cosec 60^@)

If x sin 60^(@) cos^(2)30^(@) =(tan^(2)45^(@) sec60^(@))/("cosec"60^(@)) , then find the value of x.

If x cos^2 30^@. sin 60^@=(tan^2 45^@. sec 60^@)/(cosec 60^@) then the value of x is यदि x cos^2 30^@. sin 60^@=(tan^2 45^@. sec 60^@)/(cosec 60^@) है, तो x का मान ज्ञात करें।

xcos^(2)30^(@).sin60^(@)=(tan^(2)45^(@).sec60^(@))/("cosec" 60^(@)) then the value of x is

If x sin 45^(@) cos 45^(@) tan60^(@)=tan^(2)45^(@) -cos60^(@) , then determine the value of x.

IF x sin 45^@ cos ^2 60^@ = ( tan ^2 60^@ "cosec " 30^@)/(sec 45^@ cot^2 30^@) then x=

If tan^(2) 45^(@)-cos^(2) 60^(@)=x sin 45^(@) cos45^(@) tan 60^(@) , then find the value of x.

If x tan 30^(@) = (sin 30^(@) + cos 60^(@))/( tan 60^(@) + sin 60^(@)) , then the value of x is :