The normal at the point (3, 4) on a circle cuts the circle at the point (-1,-2). Then the equation of the circle is

The normal at the point (3,4) on a circle cuts the circle at the poins (-1,-2) . Then the equation of the circle is

A foot of the normal from the point (4, 3) to a circle is (2, 1) and a diameter of the circle has the equation 2x -y -2 =0 . Then the equation of the circle is:

The foot of the normal from the point (1,2) to a circle is (3,4) and a diameter of the circle has the equation 2x+y+5=0 ,then the equation of the circle is

The equation of radical axis of two circles is x + y = 1 . One of the circles has the ends ofa diameter at the points (1, -3) and (4, 1) and the other passes through the point (1, 2).Find the equations of these circles.

The equation of radical axis of two circles is x + y = 1 . One of the circles has the ends ofa diameter at the points (1, -3) and (4, 1) and the other passes through the point (1, 2).Find the equations of these circles.

The end - point of a diameter of a circle are (-1,4) and (5,4) . The the eqauation of the circle is

The equation of radical axis of two circles is x+y=1. One of the circles has the ends ofa diameter at the points (1,-3) and (4,1) and the other passes through the point (1, 2).Find the equating of these circles.

The equation of radical axis of two circles is x + y = 1 . One of the circles has the ends ofa diameter at the points (1, -3) and (4, 1) and the other passes through the point (1, 2).Find the equating of these circles.

The point on a circle nearest to the point P(2,1) is at a distance of 4 units and the farthest point is (6, 5). Then find the equation of the circle.

The point on a circle nearest to the point P(2,1) is at a distance of 4 units and the farthest point is (6, 5). Then find the equation of the circle.