`{:(A,B,C,D,E,F,G,H,I,J,K,L,M),(1,2,3,4,5,6,7,8,9,10,11,12,13),(N,O,P,Q,R,S,T,U,V,W,X,Y,Z),(14,15,16,17,18,19,20,21,22,23,24,25,26):}`
In each of the following questions, five groups of letters are given. Four of them are alike in a certain way while one is different. Choose the odd one.

Options

A. BD
B. MP
C. NQ
D. HK

Answer

To solve the problem of identifying the odd group of letters from the given options, we will analyze each group based on the pattern of letter sequences.

### Step-by-Step Solution:

1. **Identify the Groups**: We have the following groups of letters:
- Group 1: (B, D)
- Group 2: (M, P)
- Group 3: (N, Q)
- Group 4: (H, K)

2. **Analyze Group 1 (B, D)**:
- The letters B and D are separated by one letter (C).
- Therefore, B + 1 letter = C, and C + 1 letter = D.
- This means B and D follow a pattern of skipping one letter.

3. **Analyze Group 2 (M, P)**:
- The letters M and P are separated by two letters (N, O).
- Therefore, M + 2 letters = N, O, and then P.
- This means M and P follow a pattern of skipping two letters.

4. **Analyze Group 3 (N, Q)**:
- The letters N and Q are separated by two letters (O, P).
- Therefore, N + 2 letters = O, P, and then Q.
- This means N and Q also follow a pattern of skipping two letters.

5. **Analyze Group 4 (H, K)**:
- The letters H and K are separated by two letters (I, J).
- Therefore, H + 2 letters = I, J, and then K.
- This means H and K also follow a pattern of skipping two letters.

6. **Identify the Odd One Out**:
- From the analysis, we see that:
- Group 1 (B, D) skips one letter.
- Groups 2 (M, P), 3 (N, Q), and 4 (H, K) all skip two letters.
- Therefore, the odd one out is **Group 1 (B, D)** because it follows a different pattern than the others.

### Final Answer:
The odd group is **(B, D)**.