`{:(A,B,C,D,E,F,G,H,I,J,K,L,M),(1,2,3,4,5,6,7,8,9,10,11,12,13),(N,O,P,Q,R,S,T,U,V,W,X,Y,Z),(14,15,16,17,18,19,20,21,22,23,24,25,26):}`
In each of the following questions, four groups of letters are given, three of them are alike in a certain way while one is different. Choose the odd one.

Options

A. xXYA
B. iIMP
C. hHIK
D. bBCE

Answer

To solve the problem of identifying the odd one out from the given groups of letters, we will analyze each option step by step.

### Step 1: Analyze the Groups
We have four groups of letters:
1. (A, B, C, D, E, F, G, H, I, J, K, L, M)
2. (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13)
3. (N, O, P, Q, R, S, T, U, V, W, X, Y, Z)
4. (14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26)

### Step 2: Identify Patterns
- **Group 1**: Letters from A to M (1 to 13 in numerical order).
- **Group 2**: Numbers from 1 to 13.
- **Group 3**: Letters from N to Z (14 to 26 in numerical order).
- **Group 4**: Numbers from 14 to 26.

### Step 3: Compare the Groups
- The first and second groups (A-M and 1-13) are sequential and correspond to each other (A=1, B=2, ..., M=13).
- The third and fourth groups (N-Z and 14-26) also correspond to each other in a similar sequential manner (N=14, O=15, ..., Z=26).

### Step 4: Identify the Odd One Out
All groups have a similar structure where letters correspond to their respective numerical positions. However, upon closer inspection:
- Groups 1 and 2 are both from A to M and 1 to 13 respectively.
- Groups 3 and 4 are both from N to Z and 14 to 26 respectively.

### Conclusion
Since all groups are paired correctly and follow the same pattern, we need to identify which group does not fit the sequential pattern.

The odd one out is **Group 2** (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13) because it is the only group that does not follow the letter sequence directly from A to M or N to Z.

### Final Answer
The odd one out is **Group 2**.

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