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Circle : Diameter ::?:?...

Circle : Diameter ::?:?

A

Rectangle : Diagonal

B

Diameter: Radius

C

Square : Rectangle

D

Bisector : Angle

Text Solution

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The correct Answer is:
To solve the analogy "Circle : Diameter :: ? : ?", we need to identify the relationship between the first pair of words (Circle and Diameter) and find a similar relationship in the second pair. ### Step-by-Step Solution: 1. **Identify the Relationship**: - A circle is a geometric shape, and the diameter is a line segment that passes through the center of the circle and touches two points on its boundary. The diameter divides the circle into two equal halves. 2. **Find a Similar Pair**: - We need to find a pair of words where the second word divides the first word into two equal parts, just like the diameter divides the circle. 3. **Evaluate the Options**: - **Option 1: Rectangle, Diagonal**: - A diagonal of a rectangle divides it into two equal triangles. This fits the relationship. - **Option 2: Diameter, Radius**: - The radius does not divide the diameter into two equal parts; it is a different relationship. - **Option 3: Square, Rectangle**: - A square is a specific type of rectangle, but it does not divide it into equal parts. - **Option 4: Bisector, Angle**: - A bisector divides an angle into two equal parts, but the relationship is reversed in the analogy. 4. **Choose the Correct Option**: - Since the diagonal of a rectangle divides it into two equal parts, the correct answer is **Option 1: Rectangle, Diagonal**. ### Final Answer: **Rectangle : Diagonal**

To solve the analogy "Circle : Diameter :: ? : ?", we need to identify the relationship between the first pair of words (Circle and Diameter) and find a similar relationship in the second pair. ### Step-by-Step Solution: 1. **Identify the Relationship**: - A circle is a geometric shape, and the diameter is a line segment that passes through the center of the circle and touches two points on its boundary. The diameter divides the circle into two equal halves. 2. **Find a Similar Pair**: ...
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