123, 14, 246, 56, 369, 125

Options

A. 123
B. 14
C. 246
D. 125

Explanation

To solve the problem of identifying the odd one out in the series: 123, 14, 246, 56, 369, 125, we will analyze the pattern in pairs of numbers.

### Step 1: Analyze the first pair (123, 14)
- We take the digits of 123: 1, 2, and 3.
- Calculate the sum of the squares of these digits:
- \(1^2 + 2^2 + 3^2 = 1 + 4 + 9 = 14\).
- The second number in the pair is 14, which matches our calculation.

**Hint:** Check if the sum of the squares of the digits of the first number equals the second number.

### Step 2: Analyze the second pair (246, 56)
- Take the digits of 246: 2, 4, and 6.
- Calculate the sum of the squares:
- \(2^2 + 4^2 + 6^2 = 4 + 16 + 36 = 56\).
- The second number in this pair is 56, which also matches our calculation.

**Hint:** Repeat the same process for the next pairs to identify any discrepancies.

### Step 3: Analyze the third pair (369, 125)
- Take the digits of 369: 3, 6, and 9.
- Calculate the sum of the squares:
- \(3^2 + 6^2 + 9^2 = 9 + 36 + 81 = 126\).
- The second number in this pair is 125, which does not match our calculation (should be 126).

**Hint:** Look for any inconsistencies in the pattern established by the previous pairs.

### Conclusion
- The first two pairs (123, 14) and (246, 56) follow the pattern correctly.
- However, the third pair (369, 125) does not follow the pattern since the expected value is 126, not 125.
- Therefore, the odd one out in the series is **125**.

**Final Answer:** 125