You are given two series in two rows. In the first row, a full series is given which follows a specific pattern. The second row has a series, similar to the first series but only first element of this series is produced followed by (A), (B), (C), (D) and (E) for the subsequent elements. You have to complete the series starting with a given number and answer the question that follows.
`{:("3","8","30","132","680","4110"),("4","A","B","C","D","E"):}`
What will come in place of C?

Options

A. 156
B. 136
C. 142
D. 148

Explanation

To solve the problem, we need to identify the pattern in the first series and apply it to the second series. Let's break it down step by step.

### Step 1: Identify the Pattern in the First Series
The first series is: 3, 8, 30, 132, 680, 4110.

1. **From 3 to 8**:
- We can multiply 3 by 2 and then add 2:
\[ 3 \times 2 + 2 = 6 + 2 = 8 \]

2. **From 8 to 30**:
- We can multiply 8 by 3 and then add 6:
\[ 8 \times 3 + 6 = 24 + 6 = 30 \]

3. **From 30 to 132**:
- We can multiply 30 by 4 and then add 12:
\[ 30 \times 4 + 12 = 120 + 12 = 132 \]

4. **From 132 to 680**:
- We can multiply 132 by 5 and then add 20:
\[ 132 \times 5 + 20 = 660 + 20 = 680 \]

5. **From 680 to 4110**:
- We can multiply 680 by 6 and then add 30:
\[ 680 \times 6 + 30 = 4080 + 30 = 4110 \]

### Step 2: Establish the Pattern
The pattern we observe is:
- Multiply by 2, add 2
- Multiply by 3, add 6
- Multiply by 4, add 12
- Multiply by 5, add 20
- Multiply by 6, add 30

The multipliers are increasing by 1 each time, and the numbers added are increasing as well.

### Step 3: Apply the Pattern to the Second Series
The second series starts with 4:
4, A, B, C, D, E.

1. **Finding A**:
- Multiply 4 by 2 and add 2:
\[ 4 \times 2 + 2 = 8 + 2 = 10 \quad \text{(A = 10)} \]

2. **Finding B**:
- Multiply 10 by 3 and add 6:
\[ 10 \times 3 + 6 = 30 + 6 = 36 \quad \text{(B = 36)} \]

3. **Finding C**:
- Multiply 36 by 4 and add 12:
\[ 36 \times 4 + 12 = 144 + 12 = 156 \quad \text{(C = 156)} \]

### Final Answer
The value that comes in place of C is **156**.