You are given two series in two rows. In the first row, a full series is given which follows a specific pattern. The second row has a series, similar to the first series but only first element of this series is produced followed by (A), (B), (C), (D) and (E) for the subsequent elements. You have to complete the series starting with a given number and answer the question that follows.
`{:("3","5","13","49","241","1441"),("6","A","B","C","D","E"):}`
What will come in place of C?

Options

A. 31
B. 121
C. 601
D. 111

Explanation

To solve the problem, we need to identify the pattern in the first series and then apply that pattern to the second series to find the value of C.

### Step-by-Step Solution:

1. **Identify the First Series**: The first series is given as:
- 3, 5, 13, 49, 241, 1441.

2. **Find the Pattern**:
- Start with the first number (3).
- The second number (5) can be derived as follows:
- \(3 \times 2 = 6\) and then subtract \(1\):
- \(6 - 1 = 5\).
- The third number (13) can be derived from the second number:
- \(5 \times 3 = 15\) and then subtract \(2\):
- \(15 - 2 = 13\).
- The fourth number (49) can be derived from the third number:
- \(13 \times 4 = 52\) and then subtract \(3\):
- \(52 - 3 = 49\).
- The fifth number (241) can be derived from the fourth number:
- \(49 \times 5 = 245\) and then subtract \(4\):
- \(245 - 4 = 241\).
- The sixth number (1441) can be derived from the fifth number:
- \(241 \times 6 = 1446\) and then subtract \(5\):
- \(1446 - 5 = 1441\).

3. **Establish the Pattern**:
- The pattern involves multiplying the previous number by an increasing integer (2, 3, 4, 5, 6) and then subtracting an increasing integer (1, 2, 3, 4, 5).

4. **Apply the Pattern to the Second Series**:
- The second series starts with 6:
- First number: \(6\).
- To find A:
- \(6 \times 2 - 1 = 12 - 1 = 11\) → A = 11.
- To find B:
- \(11 \times 3 - 2 = 33 - 2 = 31\) → B = 31.
- To find C:
- \(31 \times 4 - 3 = 124 - 3 = 121\) → C = 121.

5. **Conclusion**:
- The value that comes in place of C is **121**.