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You are given two series in two rows. In...

You are given two series in two rows. In the first row, a full series is given which follows a specific pattern. The second row has a series, similar to the first series but only first element of this series is produced followed by (A), (B), (C), (D) and (E) for the subsequent elements. You have to complete the series starting with a given number and answer the question that follows.
`{:("434","353","417","368","404","379"),("108","A","B","C","D","E"):}`
What will come in place of D?

A

53

B

27

C

91

D

78

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to identify the pattern in the first series and then apply that pattern to the second series to find the value of D. ### Step-by-Step Solution: 1. **Identify the First Series**: The first series given is: - 434, 353, 417, 368, 404, 379 2. **Analyze the Pattern**: - The series appears to alternate between two sequences: - Sequence 1: 434, 417, 404, 379 (decreasing) - Sequence 2: 353, 368 (increasing) 3. **Calculate the Differences in Sequence 1**: - From 434 to 417: \[ 434 - 417 = 17 \] - From 417 to 404: \[ 417 - 404 = 13 \] - From 404 to 379: \[ 404 - 379 = 25 \] - The differences are 17, 13, and 25. 4. **Calculate the Differences in Sequence 2**: - From 353 to 368: \[ 368 - 353 = 15 \] - The next number in this sequence is 379, which we can assume follows the same pattern. 5. **Establish the Pattern**: - The first sequence decreases by 17, then 13, and the second sequence increases by 15. - The differences in the first sequence are decreasing by 4 each time (17, 13). - The second sequence also seems to increase by a decreasing amount. 6. **Apply the Pattern to the Second Series**: - The second series starts with 108, and we need to find A, B, C, D, and E. - A will be calculated as follows: - For B, we subtract 17 from 108: \[ B = 108 - 17 = 91 \] - For C, we subtract 13 from B (91): \[ C = 91 - 13 = 78 \] - For D, we will subtract 9 from C (78): \[ D = 78 - 9 = 69 \] 7. **Conclusion**: - The value that comes in place of D is 69. ### Final Answer: D = 69

To solve the problem, we need to identify the pattern in the first series and then apply that pattern to the second series to find the value of D. ### Step-by-Step Solution: 1. **Identify the First Series**: The first series given is: - 434, 353, 417, 368, 404, 379 2. **Analyze the Pattern**: ...
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MCGROW HILL PUBLICATION-ADDITIONAL TOPICS IN MENTAL MATH-EXERCISE 1
  1. You are given two series in two rows. In the first row, a full series ...

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  2. You are given two series in two rows. In the first row, a full series ...

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  3. You are given two series in two rows. In the first row, a full series ...

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  4. You are given two series in two rows. In the first row, a full series ...

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  5. You are given two series in two rows. In the first row, a full series ...

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  6. You are given two series in two rows. In the first row, a full series ...

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  7. You are given two series in two rows. In the first row, a full series ...

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  8. You are given two series in two rows. In the first row, a full series ...

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  9. You are given two series in two rows. In the first row, a full series ...

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  10. You are given two series in two rows. In the first row, a full series ...

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  11. You are given two series in two rows. In the first row, a full series ...

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  12. You are given two series in two rows. In the first row, a full series ...

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  13. You are given two series in two rows. In the first row, a full series ...

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  14. You are given two series in two rows. In the first row, a full series ...

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  15. You are given two series in two rows. In the first row, a full series ...

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  16. You are given two series in two rows. In the first row, a full series ...

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  17. You are given two series in two rows. In the first row, a full series ...

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  18. You are given two series in two rows. In the first row, a full series ...

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  19. You are given two series in two rows. In the first row, a full series ...

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  20. You are given two series in two rows. In the first row, a full series ...

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