If all the numbers from 7 to 59, which are divisible by 3 are arranged in descending order then which number will be at `10^(th)` place from the bottom?

Options

A. 36
B. 39
C. 30
D. 27

Answer

To solve the problem, we need to find all the numbers between 7 and 59 that are divisible by 3, arrange them in descending order, and identify the number that is in the 10th position from the bottom.

### Step-by-Step Solution:

1. **Identify the Range**: We are looking for numbers between 7 and 59.

2. **Find Numbers Divisible by 3**: We need to find all the numbers in this range that are divisible by 3. The numbers divisible by 3 can be found by checking each number in the range:
- The smallest number greater than or equal to 7 that is divisible by 3 is 9.
- The largest number less than or equal to 59 that is divisible by 3 is 57.

3. **List the Numbers**: We can list the numbers divisible by 3 from 9 to 57:
- 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57.

4. **Arrange in Descending Order**: Now, we arrange these numbers in descending order:
- 57, 54, 51, 48, 45, 42, 39, 36, 33, 30, 27, 24, 21, 18, 15, 12, 9.

5. **Identify the 10th Number from the Bottom**: To find the 10th number from the bottom, we can count from the smallest number upwards:
- 1st from the bottom: 9
- 2nd from the bottom: 12
- 3rd from the bottom: 15
- 4th from the bottom: 18
- 5th from the bottom: 21
- 6th from the bottom: 24
- 7th from the bottom: 27
- 8th from the bottom: 30
- 9th from the bottom: 33
- 10th from the bottom: 36

Thus, the number that is at the 10th position from the bottom is **36**.

### Final Answer:
The number at the 10th place from the bottom is **36**.