`{:(A , B , C , D , E , F , G , H , I , J , K , L , M , N , O , P , Q , R ,S , T ,U , V , W ,X , Y , Z), (1 ,2 , 3 , 4 ,5, 6 , 7,8,9,10 , 11 , 12, 13, 14, 15 , 16 , 17 , 18 , 19, 20 , 21 ,22 , 23 , 24 , 25 , 26):}`
FJUL : BOQQ :: LHRX : ?

Options

A. BKPR
B. MNCC
C. HRYY
D. HMNC

Explanation

To solve the analogy problem FJUL : BOQQ :: LHRX : ?, we need to identify the pattern in the first pair (FJUL and BOQQ) and then apply that same pattern to the second pair (LHRX) to find the corresponding letters.

### Step-by-Step Solution:

1. **Identify the letters and their positions:**
- F (6), J (10), U (21), L (12)
- B (2), O (15), Q (17), Q (17)

2. **Determine the changes in positions:**
- From F to B:
- F (6) to B (2) is a decrease of 4 (6 - 4 = 2).
- From J to O:
- J (10) to O (15) is an increase of 5 (10 + 5 = 15).
- From U to Q:
- U (21) to Q (17) is a decrease of 4 (21 - 4 = 17).
- From L to Q:
- L (12) to Q (17) is an increase of 5 (12 + 5 = 17).

3. **Establish the pattern:**
- The pattern is:
- -4, +5, -4, +5

4. **Apply the pattern to LHRX:**
- L (12) - 4 = H (8)
- H (8) + 5 = M (13)
- R (18) - 4 = N (14)
- X (24) + 5 = C (3)

5. **Combine the results:**
- The resulting letters from LHRX are H, M, N, C.

### Final Answer:
The answer is HMNC.