`{:(A , B , C , D , E , F , G , H , I , J , K , L , M , N , O , P , Q , R ,S , T ,U , V , W ,X , Y , Z), (1 ,2 , 3 , 4 ,5, 6 , 7,8,9,10 , 11 , 12, 13, 14, 15 , 16 , 17 , 18 , 19, 20 , 21 ,22 , 23 , 24 , 25 , 26):}`
QDXM : SFYN :: UIOZ: ?

Options

A. WKPA
B. QNLA
C. LPWA
D. PAQM

Explanation

To solve the analogy question QDXM : SFYN :: UIOZ : ?, we will follow the same pattern of letter transformations as shown in the first pair.

### Step-by-Step Solution:

1. **Identify the first pair**:
- QDXM and SFYN.

2. **Analyze the transformations**:
- **From Q to S**:
- Q is the 17th letter and S is the 19th letter.
- Transformation: 17 + 2 = 19.
- **From D to F**:
- D is the 4th letter and F is the 6th letter.
- Transformation: 4 + 2 = 6.
- **From X to Y**:
- X is the 24th letter and Y is the 25th letter.
- Transformation: 24 + 1 = 25.
- **From M to N**:
- M is the 13th letter and N is the 14th letter.
- Transformation: 13 + 1 = 14.

3. **Establish the pattern**:
- The pattern observed is:
- First letter: +2
- Second letter: +2
- Third letter: +1
- Fourth letter: +1

4. **Apply the pattern to the second pair (UIOZ)**:
- **From U**:
- U is the 21st letter.
- 21 + 2 = 23, which is W.
- **From I**:
- I is the 9th letter.
- 9 + 2 = 11, which is K.
- **From O**:
- O is the 15th letter.
- 15 + 1 = 16, which is P.
- **From Z**:
- Z is the 26th letter.
- 26 + 1 = 27, but since there are only 26 letters, we wrap around to A (1st letter).

5. **Combine the results**:
- The resulting letters are W, K, P, A.

6. **Final answer**:
- Therefore, UIOZ transforms to WKPA.

### Conclusion:
The answer is WKPA.