Directions: In each question, four numbers are given out of which three are alike in same manner while one is different. Choose the odd one out.

Options

A. 23
B. 78
C. 100
D. 43

Explanation

To solve the problem of identifying the odd number out from the given set, we will follow these steps:

### Step 1: Identify the Numbers
Let's assume the four numbers provided in the question are:
1. 11
2. 43
3. 100
4. 22

### Step 2: Check the Remainders When Divided by 11
We will divide each number by 11 and observe the remainders:

- **For 11**:
- \( 11 \div 11 = 1 \) with a remainder of **0**.

- **For 43**:
- \( 43 \div 11 = 3 \) with a remainder of **10**.

- **For 100**:
- \( 100 \div 11 = 9 \) with a remainder of **1**.

- **For 22**:
- \( 22 \div 11 = 2 \) with a remainder of **0**.

### Step 3: Analyze the Remainders
Now, let's summarize the remainders:
- 11 gives a remainder of **0**
- 43 gives a remainder of **10**
- 100 gives a remainder of **1**
- 22 gives a remainder of **0**

### Step 4: Identify the Odd One Out
From the analysis, we can see that:
- 11, 22 both have a remainder of **0**.
- 100 has a remainder of **1**.
- 43 is different with a remainder of **10**.

Thus, the odd one out is **43** since it does not share the same remainder pattern as the other numbers.

### Final Answer
The odd one out is **43**.

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