Choose the number pair/group which is different from others.

Options

A. `7-147`
B. `6-108`
C. `5-75`
D. `3-99`

Explanation

To solve the problem of identifying the number pair/group that is different from the others, we will follow these steps:

### Step 1: Understand the Problem
The question asks us to find a number pair or group where the second number divided by the square of the first number gives a different quotient compared to the others.

### Step 2: Analyze Each Option
We will evaluate each option by calculating the quotient of the second number divided by the square of the first number.

1. **Option 1: (7, 147)**
- First number = 7
- Second number = 147
- Calculate the square of the first number: \(7^2 = 49\)
- Calculate the quotient: \( \frac{147}{49} = 3\)

2. **Option 2: (6, 108)**
- First number = 6
- Second number = 108
- Calculate the square of the first number: \(6^2 = 36\)
- Calculate the quotient: \( \frac{108}{36} = 3\)

3. **Option 3: (5, 75)**
- First number = 5
- Second number = 75
- Calculate the square of the first number: \(5^2 = 25\)
- Calculate the quotient: \( \frac{75}{25} = 3\)

4. **Option 4: (3, 99)**
- First number = 3
- Second number = 99
- Calculate the square of the first number: \(3^2 = 9\)
- Calculate the quotient: \( \frac{99}{9} = 11\)

### Step 3: Compare the Quotients
Now we compare the quotients obtained from each option:
- Option 1: Quotient = 3
- Option 2: Quotient = 3
- Option 3: Quotient = 3
- Option 4: Quotient = 11

### Step 4: Identify the Odd One Out
From our calculations, we can see that Options 1, 2, and 3 all yield a quotient of 3, while Option 4 yields a quotient of 11. Therefore, the odd one out is:

**Option 4: (3, 99)**

### Final Answer
The number pair/group that is different from the others is **Option 4: (3, 99)**.

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