In each of these question, four groups of letters are given. Three of them are alike in a certain way while one is different select the one which is different.

Options

A. SUWY
B. MOQS
C. CEGI
D. HJMO

Explanation

To solve the problem of identifying the odd group of letters from the given options, we will analyze each group step by step.

### Step 1: Analyze the first group - SUWY
- The letters are S, U, W, and Y.
- If we look at the pattern:
- S → T (add 1) → U
- U → V (add 1) → W
- W → X (add 1) → Y
- The pattern here is that each letter is followed by the next letter in the alphabet (a difference of +1).

### Step 2: Analyze the second group - MOQS
- The letters are M, O, Q, and S.
- The pattern is:
- M → N (add 1) → O
- O → P (add 1) → Q
- Q → R (add 1) → S
- Again, we see that each letter is followed by the next letter in the alphabet (a difference of +1).

### Step 3: Analyze the third group - CEGI
- The letters are C, E, G, and I.
- The pattern is:
- C → D (add 1) → E
- E → F (add 1) → G
- G → H (add 1) → I
- This group also follows the same pattern of each letter being followed by the next letter in the alphabet (a difference of +1).

### Step 4: Analyze the fourth group - HJMO
- The letters are H, J, M, and O.
- The pattern is:
- H → I (add 1) → J
- J → K (add 1) → L (but we skip L to go to M)
- M → N (add 1) → O
- Here, we see that after J, we skip L to go to M, which breaks the pattern of having a consistent difference of +1.

### Conclusion
- The first three groups (SUWY, MOQS, CEGI) all follow the same pattern of having a difference of +1 between consecutive letters.
- The fourth group (HJMO) does not follow this consistent pattern because it skips a letter (L) between J and M.

Therefore, the odd one out is **HJMO**.