Home
Class 11
BIOLOGY
In each segment, exoskeleton have harden...

In each segment, exoskeleton have hardened plates called sclerites
`{:("a) Dorsal sclerite","1) Sternum"),("b) Ventral sclerite","2) Pleura"),("c) Lateral sclerite","3) Tergum"),("d) Sclerite present in","4) Pronotum"),(" protharx",),(,"5) Metanotum "):}`

A

a-1,b-2, c-3, d-4

B

a-3, b-2, c-3, d-4

C

a-3, b-1, c-2, d-4

D

a-3, b-2, c-1, d-5

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • STRUCTURAL ORGANISATION IN ANIMALS

    AAKASH SERIES|Exercise EXERCISE-I (COCKROACH) (DIGESTIVE SYSTEM)|2 Videos

  • STRUCTURAL ORGANISATION IN ANIMALS

    AAKASH SERIES|Exercise EXERCISE-I (COCKROACH) (RESPIRATORY SYSTEM)|2 Videos

  • STRUCTURAL ORGANISATION IN ANIMALS

    AAKASH SERIES|Exercise EXERCISE-I (REPRODUCTIVE SYSTEM)|7 Videos

  • STRATEGIES FOR ENHENCEMENT IN FOOD PRODUCTION

    AAKASH SERIES|Exercise EXERCISE-III|68 Videos

  • THE LIVING WORLD

    AAKASH SERIES|Exercise EXERCISE-III (Previous AIPMT/NEET Questions) |14 Videos

Similar Questions

Explore conceptually related problems

Match the following {:("1) Dorsal blood vessel","a) Clitellum "),("2) Gential openingst","b) Ventral surface "),("3) Buccal segement ","c) Peristomium "),("4) Glandular tissue in ","d) Dark median"),(" 14, 15, 16"," dorsal line "):}

Match the following with respective "sclerite" in cockroach feature {:("1)Located in between","a) Vertex"),(" two compound eyes",),("2) Largest in head","b) Frons"),(" regions below vertex",),("3) Rectangular in shape","c) Clypeus"),("4) Covering sides of ","d) Genae"),(" the head",),("5) Borders occipital","e) Occiput"),("foramen",):}

Match List (Distinguishing features based on chromosomal appearance) with List -II (Stage of meiosis) and select the correct answer using the codes given below the list {:(,"List-I",,"List-II"),("(A)","Terminalized chaismata",1,"Pachytene"),((B) ,"Exchange of segments of chromatids",2,"Zygotene"),((C ),"Synapsis of homologous chromosomes",3,"Diakinesis"),((D),"Appearance of chiasmata",4,"Leptotene"),(,,5,"Diplotene"):}

The only electron in the hydrogen atom resides under ordinary conditions on the first orbit. When energy is supplied, the electron moves to higher energy orbit depending on the amount of energy absorbed. When this electron returns to any of the lower orbits, it emits energy. Lyman series is formed when the electron returns to the lowest orbit while Balmer series is formed when the electron returns to second orbit. Similarly, Paschen, Brackett and Pfund series are formed when electron returns to the third, fourth orbits from higher energy orbits respectively (as shown in figure) Maximum number of lines produced when an electron jumps from nth level to ground level is equal to (n(n-1))/(2) . For example, in the case of n = 4, number of lines produced is 6. (4 rarr 3, 4 rarr 2, 4 rarr 1, 3 rarr 2, 3 rarr 1, 2 rarr 1) . When an electron returns from n_(2) to n_(1) state, the number of lines in the spectrum will be equal to ((n_(2) - n_(1))(n_(2)-n_(1) +1))/(2) If the electron comes back from energy level having energy E_(2) to energy level having energy E_(2) then the difference may be expressed in terms of energy of photon as E_(2) - E_(1) = Delta E, lambda = (h c)/(Delta E) . Since h and c are constant, Delta E corresponds to definite energy, thus each transition from one energy level to another will prouce a higher of definite wavelength. THis is actually observed as a line in the spectrum of hydrogen atom. Wave number of the line is given by the formula bar(v) = RZ^(2)((1)/(n_(1)^(2)) - (1)/(n_(2)^(2))) Where R is a Rydberg constant (R = 1.1 xx 10^(7)) (i) First line of a series : it is called .line of logest wavelength. or .line of shortest energy.. (ii) Series limit of last of a series : It is the line of shortest wavelength or line of highest energy. In a single isolated atom in electron makes transition from 5^(th) excited state to 2^(nd) state the maximum number of different types of photons observed as

Numerous forms of the periodic table have been devised from time to time. A modern version which is most convenient and widely used is the long or extended from of periodic table. The aufbau principle and the electronic configuration of atoms provide a theoretical foundation for the periodic classification. The horizontal rows are called periods. There are altogether seven periods. The first period consists of 2 elements. The subsequent periods consists of 8, 8,18, 18 and 32 elements respectively. The seventh period is incomplete and like the sixth period would have maximum of 32 elements. Elements having similar outer electronic configurations in their atoms are grouped in vertical columns. These are referred to as groups or families. According to the recommendations of IUPAC, the groups are numbered 1 to 18 replacing the older notation of groups 0, IA, IIA, ....VIIA, VIII, IB.....VIIB. Each successive period in the periodic table is associated with the filling up next higher principal energy level following aufbau sequence. The number of elements in each period is twice the number of atomic orbitals available in the energy level that is being filled. All the elements are classified into four blocks, i.e., s-block, p-block, d-block, and f-block depending on the type of atomic orbitals that are being filled with electrons. Elements A, B, C, D and E have the following electronic configuration: (A) 1s^2, 2s^2 2p^1 (B) 1s^2, 2s^2 2p^6 , 3s^2 3p^1 (C ) 1s^2, 2s^2 2p^6 , 3s^2 3p^3 (D) 1s^2 , 2s^2 2p^6 , 3s^2 3p^5 (E) 1s^2 , 2s^2 2p^6 , 3s^2 3p^6 Which among these will belong to same group in the periodic table ?

Let us do the following activity to understand the mendelian principles of heredity. Materaials required: a. 3cm length and 1 cm breadth chart pieces -4 b. 2 cm length and 1 cm breadth chart pieces -4 c. Red byuttons -4 d. white buttons -4 e. chart, scale, sketch pen penil, 2 bags. Method: Prepare a chart with 2x2 boxes along with numbe and symbol as shown in the figure. Game 1: Monohybrid cross (starting with hybrid parents) To start with take 1,2 or 3,4 . In case you start 1,2 pik all the 16 log and short pieces and prepare such paris in each of which you have a long and short piece. Take 4 pairs each of long and short strips and put them in two separate bags. Now each bag contains 8 strips (4 long and 4short). One bag say 'A' represents mael and the bag 'B' represents female . Now rendomly pick one strip each from bag A and B and put them together in the 1 on the chart. Keep picking out the strips and arrange them in the same manner till your bags are empty. Same time your boxes in the chart are filled with paris of strips. you might have got the following combinations, two long strips, one long and one short strip, two short strips. (Q) E. What can you coclude from this game?

Ideal gas equation is represented as PV=nRT . Gases present in the universe were found ideal n the Boyle's temperature range only. The compressibility factor for an ideal gas, Z= (PV)/(nRT) . The main cause to show deviations were due to wrong assumptions made bout forces of attractions (which becomes significant at high pressure). olume occupied by molecules V, in PV = nRT, is supposed to be volume of as or, the volume of container in which gas is placed by assuming that aseous molecules do not have appreciable volume. Actual volume of the as is that volume in which each molecule of a gas can move freely. If olume occupied by gaseous molecule is not negligible, then the term V hould be replaced by the ideal volume which is available for free motion of ach molecule of gas. Similarly for n moles of gas V_("actual") = V-nb The excluded volume can be calculated by considering bimolecular collisions. The excluded volume is the volume occupied by the sphere of 2r for each pair of molecule. Thus, excluded volume for one pair of molecules = 4/3 pi (2r)^3 = (4 xx 8 pi r^3)/3 The excluded volume for 1 molecule = 2/3 xx 8 pi r^3 = 4 xx (4/3 pi r^3) = 4V The excluded volume for N molecules = 4NV = b (where N is Avogadro's No.) The compressibility factor for N_2 at -50^@C and 800 atm pressure is 1.95. Number of moles of N_2 required to fill a balloon of 100 L capacity is :

AAKASH SERIES-STRUCTURAL ORGANISATION IN ANIMALS-EXERCISE-I (COCKROACH) (EXTERNAL CHARACTERS)
  1. The term 'vasa varicosa' was introduced by

    Text Solution

    |

  2. The two common species of cockroaches found in India are:

    Text Solution

    |

  3. The name Periplaneta americana is coined by

    Text Solution

    |

  4. Which one of the following function is not done by 'exoskeleton' of co...

    Text Solution

    |

  5. Which of the following is not real 'tagmata' of body of cockroach?

    Text Solution

    |

  6. In each segment, exoskeleton have hardened plates called sclerites {...

    Text Solution

    |

  7. Sclerites are joined to each other by thin and flexible membrane calle...

    Text Solution

    |

  8. Head of cockroach is hypognathous beccause

    Text Solution

    |

  9. Match the following with respective "sclerite" in cockroach feature  ...

    Text Solution

    |

  10. At the base of each antenna of cockroach there is a small whitish spot...

    Text Solution

    |

  11. Mouth parts of cockroach are

    Text Solution

    |

  12. Which one is not correct wrt to 'labrum'

    Text Solution

    |

  13. Arrange the different layers in the body wall from outer to inner 1)...

    Text Solution

    |

  14. Choose the correct statement regarding 'coelom of Periplaneta american...

    Text Solution

    |

  15. Match the following w.r.t to locomotion in cockroach {:("1) Prothora...

    Text Solution

    |

  16. Write the correct sequence of legs in tripod inside and left side {:...

    Text Solution

    |

  17. Prothorax contain which of the following components

    Text Solution

    |

  18. Match the following {:("1) Crop ","a) Sieve & grinding mill"),("2) G...

    Text Solution

    |