x(x^(2)-1)(dy)/(dx)=1,y=0" when "x=2...

x(x^(2)-1)(dy)/(dx)=1,y=0" when "x=2

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2xy + y^(2) - 2x^(2)(dy)/(dx) = 0, y = 2 when x = 1

2xy + y^(2) - 2x^(2)(dy)/(dx) = 0, y = 2 when x = 1

2xy + y^(2) - 2x^(2)(dy)/(dx) = 0, y = 2 when x = 1

2 x y+y^2-2 x^2 (dy)/(dx)=0 , y=2 when x=1

Solution of differential equation y-x(dy)/(dx)=y^(2)+(dy)/(dx), when x=1,y=2, is

Solve the differential equation x(x^2-1)(dy)/(dx)=1 , given that when x=2, y=0 .

Solve the differential equation x(x^2-1)(dy)/(dx)=1 , given that when x=2, y=0 .

(dy)/(dx)=y tan x , y=1 when x=0

(x^(3)+x^(2)+x+1)(dy)/(dx)=2x^(2)+x;y=1 when x=0

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