A parallel plate capacitor contanins a mica sheet (thickness ` 0. 5+xx10^(-3) m`) . And a sheet of fiber (thickness `0. 5 xx 10^(-3) m`) . The dielectric constant of mica is `8` and that of thye fiber is `2.5` Assuming that the fiber breaks down when subjected to an electric field of ` 6.4 xx 10^6 Vm^(-1)`. , find the maximum safe voltage that can be applied to the capacitor.

A parallel-plate capacitor contains a mica sheet (thickness 10^(-3) m) and a sheet of fibre (thickness 0.5xx10^(-3) m). The dielectric constant of mica is 8 and that of the fibre is 2.5. Assuming that the fibre breaks down when subjected to an electric field of 6.4xx10^(6)Vm^(-1) , find the maximum safe voltage that can be applied to the capacitor.

The is one parallel plate air capacitor having plate area 40 cm^(2) and separation between the plates equal to 0.1 mm. Dielectric strength of air is 3xx 10^(6) V/m. find maximum rms voltage that can be applied across capacitor without electric breackdown.

A parallel plate condenser consists of two plates each of area 100cm^(2) . They are separated by mica sheet of thickness 8.85 mm. If the relative permittivity of mica is 6. Then capacity of parallel plate condenser is

A parallel-plate capacitor is made up of 15 strips, each of 6 cm xx 4 cm, separated by sheet of mica of dielectric coefficent 6 and constant thickness of 0.15 mm. Calculate its capacitance.

A parallel-plate capacitor of consists of 26 metal strips, each of 3cmxx4cm , separated by mica sheets of dielectric constant 6 and uniform thickness 0.2 mm. find the capacitance.

A parallel plate capacitor with plate area 8xx10^(-3)m^(2) , and plate separation 0.1 cm is connected to a battery of 100 V. Calculate the dielectric constant of the medium filled completely between both the plates if it can store a charge equal to 1.5xx10^(-7)C .

A parallel plate capacitor has plates A and B each of area 0.5m^2 and a plate separation of 0.2 m. A dielectric slab of thickness 0.1m and dielectric constant 2.5 is placed between the two plates as shown - (a) FInd the capacitance of the capacitor, if the surface charge densities of the two plates are 8.854xx10^(-10)Cm^(-2) . (b) Graphically represent the variation of electric field between the two plates from A to B.