A circle of radius 5 is tangent to the line `4x-3y=18` at M(3, -2) and lies above the line. The equation of the circle is

A circle is tangent to line 3x-4y+1=0 at (1,1) and is normal to line 2x+y-5=0 .then find the equation of circle

A circle has radius 3 units and its centre lies on the line y = x - 1. Find the equation of the circle if it passes through (7, 3)

A circle has radius 3 units and its centre lies on the line y=x-1. Find the equation of the circle if it passes through (7,3).

A circle has radius 3 units and its centre lies on the line y=x-1. Find the equation of the circle,if it passes through (7,3) .

A circle has radius 3 units and its centre lies on the line y=x-1. Find the equation of the circle if it passes through (7,3).

A circle has two of its diameters along the lines 2x + 3y - 18 =0 and 3x - y - 5 =0 and touches the line x + 2y + 4=0. Equation of the circle is

The line 5x-y=3 is a tangent to a circle at the point (2,7) and its centre is on theline x+2y=19. Find the equation of the circle.

The line 5x - y = 3 is a tangent to a circle at the point (2, 7) and its centre is on theline x + 2y = 19 . Find the equation of the circle.

The two diameters of a circle are segments of the straight lines x-y =5 and 2x+y =4 .If the radius of the circle is 5 then the equation of the circle is

Line 2x+3y+1=0 is a tangent to the circle at (1,-1). This circle is orthogonal to a circle which is drawn having diameter as a line segment with end points (0, -1) and (-2, 3). Then the equation of the circle is