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" 12.थF्र "10^(2y)=25" ,तो "10^(-y)" (A)...

" 12.थF्र "10^(2y)=25" ,तो "10^(-y)" (A) "(1)/(5)" (B) "(1)/(50)" ar ह "(1)/(50)" (C) "x=2,y=2" (D) "x=3

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If 10^(2y)=25, then 10^(-y) equals -(1)/(5)(b)(1)/(50) (c) (1)/(625) (d) (1)/(5)

If 10^(2y)=\ 25\ , then 10^(-y) equals (a) -1/5 (b) 1/(50) (c) 1/(625) (d) 1/5

If A=[(1,0),(1/2,1)] then A^50 is (A) [(1,25),(0,1)] (B) [(1,0),(25,1)] (C) [(1,0),(0,50)] (D) [(1,0),(50,1)]

If A=[(1,0),(1/2,1)] then A^50 is (A) [(1,25),(0,1)] (B) [(1,0),(25,1)] (C) [(1,0),(0,50)] (D) [(1,0),(50,1)]

The solution of the differential equation (x(dy)/(dx) - y)/(sqrt(x^(2) - y^(2))) = 10x^(2) is a) sin^(-1)((y)/(x)) - 5x^(2) = C b) sin^(-1)((y)/(x)) - 5x^(2) = C c) (y)/(x) = 5x^(2) + C d) sin^(-1)((y)/(x)) = 10x^(2) + Cx

If 2x+3y=5 and 3x+2y=10 then x-y= (a) 3 (b) 4 (c) 5 (d) 6

If x^3-2x^2y^2+5x+y-5=0 and y(1)=1 , then (a) y^(prime)(1)=4/3 (b) y'(1)=-4/3 (c) y''(1)=-8(22)/(27) (d) y^(prime)(1)=2/3

If x^3-2x^2y^2+5x+y-5=0 and y(1)=1 , then (a) y^(prime)(1)=4/3 (b) y'(1)=-4/3 (c) y''(1)=-8(22)/(27) (d) y^(prime)(1)=2/3

If x^3-2x^2y^2+5x+y-5=0 and y(1)=1 , then (a) y^(prime)(1)=4/3 (b) y'(1)=-4/3 (c) y''(1)=-8(22)/(27) (d) y^(prime)(1)=2/3

A parabola is drawn through two given points A(1,0) and B(-1,0) such that its directrix always touches the circle x² + y^2 = 4. Then, The locus of focus of the parabola is (a) (x^(2))/(4) +(y^(2))/(3) = 1 (b) (x^(2))/(4) +(y^(2))/(5) =1 (c) (x^(2))/(3)+(y^(2))/(4) = 1 (d) (x^(2))/(5)+(y^(2))/(4)=1