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[" 78."(sin^(2)3A)/(sin^(2)A)=(cos^(2)3....

[" 78."(sin^(2)3A)/(sin^(2)A)=(cos^(2)3.4)/(cos^(2)4)=],[" (A) "cos2A],[" (B) "8cos2A],[" (C) "quad (1)/(8)cos2A],[" (D) "(1)/(2)cos2A]

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