The following results are obtained in several dihybrid test crosses in an organism considering three genes loci Aa,Bb and Cc.
a. In test cross with AaBb the number of recombinants and parental combinations are 50 and 950 respectively.
b. In TC with AaCc the number of Rc and PC are 75 and 425 respectively.
c. In TC with BbCc the number of RC and PC are 160 and 640 respectively.
basing on the above result identify the gene loci of the three genes /prepare a genetic map of the three genes.

Explanation

First let us calculate % of RC in each case and distance between the genes (in map units).
% of recombination of `TC(a)=50/100xx100=5%`
`=5` map units /,cM