Home
Class 12
MATHS
The length of the tangent from any point...

The length of the tangent from any point on the circle to the circle `(x-3)^2 + (y + 2)^2 =5r^2` to the circle ` (x-3)^2 + (y + 2)^2 = r^2` is 4 units. Then the area between the circles is

Promotional Banner

Similar Questions

Explore conceptually related problems

The length of the tangent from any point on the circle (x-3)^2 + (y + 2)^2 =5r^2 to the circle (x-3)^2 + (y + 2)^2 = r^2 is 4 units. Then the area between the circles is

If the length of the tangent from any point on the circle (x-3)^(2)+(y+2)^(2)=5r^(2) to the circle (x-3)^(2)+(y+2)^(2)=r^(2) is 4 units, then the area between the two circles in sq. units is

If the length of the tengent from any point on the circle x-3^2+y+2^2= 5r^2 to the circle x-3^2+y+2^2 = r^2 is 16 unit,then the area between the two circles in sq unit is

The length of the tangent drawn from any point on the circle : x^2+y^2 -4x+2y-4=0 to the circle x^2+y^2-4x+6y=0 is :

The length of the tangent from a point on the circle x^(2)+y^(2)+4x6y-12=0 to the circle x^(2)+y^(2)+4x6y+4=0 is

The length of the tangent from the point (1,-4) to the circle 2x^2+2y^2-3x+7y+9=0

The length of the tangent from (5, 1) to the circle x^2+y^2+6x-4y-3=0 is :

The length of tangent from the point (2,-3) to the circle 2x^2 +2y^2=1 is

The length of tangent from the point (2,-3) to the circle 2x^(2)+2y^(2)=1 is