sech! (2) + cosech ! (-1)

"Sech"^(-1)(1/2) - "Cosech"^(-1) (3/4) =

sech^(2)("tan"h^(-1)1/2)+cosech^(2)(coth^(-1)3)=

Ascending order of A = sinh 0, B = cosh 0, C = sech 1, D = cosech 1 is

Assertion (A) : "cosech"^(-1)(2)=log_(e )((1+sqrt(5))/(2)) Reason (R ) : "Cosech"^(-1)(x)=log_(e ) ((1+sqrt(1+x^(2)))/(2))

If coth x = sec theta , then cosech x =

If cosh(x)=sec alpha then "cosech"(x)=

If A = "Tanh"^(-1) (1//2) + "Coth"^(-1) (2), "B = sinh "("Cosh"^(-1)9) . "C = sech"^(2) ("Tanh"^(-1) 1//2)+ "cosech"^2 ("Coth"^(-1) 3) then