A piece of copper having a rectangular cross section of 15.2 mm x 19.1 mm is pulled in tension with 44,500 N force, producing only elastic deformation. Calculate the resulting strain.`Y_(Cu)=1.2 xx 10 ^(11) N//m^(2).`

Explanation

`Y= ("Longitudinal stress")/("Longitudianal strain")`
`therefore` ongitudinal strain
`= ("Stress")/(Y) = (F)/(AY) = (F)/(l xx b xx Y)`
`= (44500)/(15.2 xx 10 ^(-3) xx 19.1 xx 10 ^(-3) xx 1.2 xx 10^( + 11))=0.00127`
`~~ 1.27 xx 10 ^(-3)`