The adjacent graph shows the extension `(DeltaI)` of a wire of length 1 m suspended from the top of a roof at one end with a load W connected to the other end. If the cross-sectional area of the wire is `10^(-6) m ^(2),` calculate The Young's modulus of the material of the wire is ........

Options

A. ` 2 xx 10 ^(11) Nm^(-2)`
B. `5 xx 10 ^(6) Nm ^(-2)`
C. `2 xx 10 ^(6) Nm ^(-2)`
D. `5 xx 10 ^(11) Nm ^(-2)`

Answer

A

Explanation

From the graph it can be observed that load of 100 N suspended at the end of wire and length increased by `5 xx 10 ^(-4) m. A = 10 ^(-6) m ^(2)` is given. Length of wire =1 m
`therefore` Young modulus
`Y= (FL)/(A Delta L)`
`= (100 xx 1 )/(10 ^(-6) xx 5 xx 10 ^(-4)) =2 xx 10 ^(11) Nm ^(-2)`