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Work done in stretching a wire of length...

Work done in stretching a wire of length 1 m and of cross-sectional area `1 mm^(2)` through 2 mm if Young's modulus of the material of the wire is `2 xx 10 ^(11) N//m^(2)` is .......

A

400 J

B

40 J

C

4 J

D

`0.4` J

Text Solution

Verified by Experts

The correct Answer is:
D
`Y= (F)/(A). (L)/(Delta L ) implies F = (YA Delta L )/(L)`
`therefore ` Work W =` 1/2 F. Delta L`
`=1/2 (Y A Delta L xx Delta L )/( L )`
`=1/2 (YA (Delta L ) ^(2))/( L )`
`=1/2 xx(2xx10^(11) xx10^(-6) xx(2xx10^-3)^(2))/(1)`
`=4 xx 10 ^(-1)`
`therefore W = 0.4 J`
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