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Two strips of metal are riveted together at their ends by four rivets, each of diameter 6.0 mm. What is the maximum tension that can be exerted by the riveted strip if the shearing stress on the rivet is not to exceed `6.9 xx 10 ^(7)` Pa ? Assume that each rivet is to carry one quarter of the load.

Text Solution

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Diameter of each rivet `=6.0` mm
`therefore` Radius `r = 3.0 mm = 3 xx 10 ^(-3) m`
Suppose tangential (shear) force on each rivet of strip is F
Shear force on each rivet = F and shear stress on each rivet `= F/A = (F _(max))/(A) `
and maximum shearing stress on each rivct `= therefore (F _(max))/(A) = 6.9 xx 10 ^(7)`
`therefore F _(max) = 6.9 xx 10 ^(7) xx A`
`= 6.9 xx 10 ^(7) xx pi r ^(2)`
`= 3.14 xx (3.0 xx 10 ^(-3)) xx 6.9 xx 10 ^(7) = 1952N`
`therefore` Total load on four river `= 4 xx 1952 = 7808 N `
`~~7.8 xx 10 ^(3) N`
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