Home
Class 11
PHYSICS
What is stopping distance for vehicle ?...

What is stopping distance for vehicle ?

Text Solution

Verified by Experts

When brakes are applied to a moving vehicle, the distance it traavels before stopping is called stopping distance.
Suppose, the velocity of moving vehicle is `v_(0).` After applying brakes retardation : -a
Distance covered : `d _(s)` (stopping distance)
Final velocity `:v =0`
In equation` v ^(2) -v _(0) ^(2) = 2ax`
`therefore 0- v _(0) ^(2) = 2 (-a ) (d_(s)) (because v = 0, a =-a , s = d _(s))`
`therefore v _(0) ^(2) = 2ad_(s)`
`therefore d _(s) =(v_(0) ^(2))/(2a)`
Here, a is value of retardation and it is constant. Thus, stopping distance is proporational to square of the initial velocity.
`therefore d_(s) prop v _(0) ^(2)`
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A STRAIGHT LINE

    KUMAR PRAKASHAN|Exercise SECTION-A TRY YOUR SELF (VSQs)|52 Videos
  • MOTION IN A STRAIGHT LINE

    KUMAR PRAKASHAN|Exercise SECTION-B|58 Videos
  • MECHANICAL PROPERTIES OF FLUIDS

    KUMAR PRAKASHAN|Exercise QUESTION PAPER (SECTION -C)|3 Videos
  • OBJECTIVE QUESTIONS AS PER NEW PAPER STYLE

    KUMAR PRAKASHAN|Exercise CHAPTER - 8 (Match Type questions)|5 Videos

Similar Questions

Explore conceptually related problems

If the speed of a vehicle become 3 times for a given deceleration its stopping distance become .....

What will be the stopping distance if the initial velocity is doubled ?

What is stopping potential?

What will be distance covered by vehicle after applying brakes with retardation 2m //s^(2) if its velocity is 1.8 km//h ?

A car is moving with a velocity of 10 m/s. Suddenly driver sees a child at a distance of 30 m and he applies the brakes, it produced a uniform retardation in car and car stops in 5 second. Find (mass of car=1000 kg) the stopping distance of car will the car hit the child the retardation in car resistive force on car

A driver travelling at speed 36 kmh^(-1) sees the light trun red at the intersection. If his reaction time is 0.6s, and then the car can deaccelerate at 4 ms^(-2) . Find the stopping distance of the car.

What would be the stopping distance if the velocity of vehicle becomes three times ?

For the given vehicle, its stopping distance is proportional to .......... of the speed.

On what factors, does the stopping distance depend ?

What will be distance covered byu vehicle after applying breakes with retardation 8 m//s ^(2) if its velocity is 72 km/h ?