A spring with one end attached to a mass and the other to a rigid support is stretched and released.

Options

A. Magnitude of acceleration, when just released is maximum
B. Magnitude of acceleration, when at equilibrium position is maximum
C. Speed is maximum when mass is at equilibrium position
D. Magnitude of displacement is always maximum whenever speed is minimum

Answer

A, D

Explanation

When spring is stretched by x, restoring force will be `F =- kx`
Potential energy of the stretched spring,
`PE = 1/2 kx^(2)`
When particle is released it will execute SHM about equilibrium position.
Acceleration will be `a = F/m = (-kx)/(m)`
At equilibrium position,` x =0 impliesa=0`
Hence, when just released, x is maximum
Hence, acceleration is maximum. Thus option (a) is correct.
At equlibrium, P.E. will be converted to K.E. hence, K.E., will be maximum and hence, speed will be maximum.