Refer to the graph in figure. Match the following

Options

A.
B.
C.
D.

Explanation

We have to analyse slope of each curve i.e., `(dx)/(dt)`
For peak points `(dx)/(dt) ` will be zero as x is maximum at peak points.
For graph (a). These is a point (B) for which displaceent is zero. So, a matches with (iii) In a graph (b),x is positive `(gt 0)` throughout and has a point `B_(1)` with `V = (dx)/(dt) =0.` As at point of curvature charges `a =0, ` So b mathces with (ii)
In grph (c ), slope `V = (dx)/(dt)` is negative hence, velocity will be negative . So, it matches with (iv)
In graph (d),. as slope `V = (dx)/(dt) ` is positive hence, `V gt 0`
Hence, d matches with (i)