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H(2)S, a toxic gas with rotten egg like ...

`H_(2)S`, a toxic gas with rotten egg like smell, is used for the qualitative analysis. If the solubility of `H_(2)S` in water at STP is 0.195 m, calculate Henry's law constant.

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It is given that the solubility of `H_(2)S` in water at STP is 0.195 m, i.e., 0.195 mol of `H_(2)S` is dissolved in 1000 g of water.
Moles of water `= (1000)/(18)=55.56` mol
`therefore` Mole fraction of `G_(2)S, X_(H_(2)O)`
`= ("Moles of "H_(2)S)/("Moles of "H_(2)S+"Moles of water")`
`= (0.195)/(0.195+55.56)=0.0035`
At STP, pressure (p) = 0.987 bar According to
Henry.s law : `p=K_(H).x`
`K_(H)=(p)/(x)=(0.987)/(0.0035)=282` bar.
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