The total pressure for volatile components A and B is 0.02 bar at equilibrium. If the mole fractions at component A is 0.2, then, what will be the partial pressure of component B ?

Options

A. 0.02 bar
B. 0.04 bar
C. 0.016 bar
D. 0.2 bar

Answer

C

Explanation

`X_(A)+X_(B)=1`
`therefore 0.2+X_(B)=1 " " therefore X_(B)=0.8`
`p_(B)=p.X_(B)=(0.02)(0.8)`
`therefore p_(B)=0.016` bar