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To prepare solution of certain substance...

To prepare solution of certain substance, 300 gm is used for 25% solution and 400 gm for 40% solution, then what is the mass percentage of solute present in this solution mixture ?

A

`33.57`

B

`66.43`

C

`87.23`

D

`19.24`

Text Solution

Verified by Experts

The correct Answer is:
A

In solution - 1, mass of solute `= (25)/(100)xx300=75` gm
In solution - 2, mass of solute `=(40)/(100)xx400=160` gm
So, total mass of solute on mixing two solution is = 235 gm
So, total mass of solution = 700 gm
So, % solute present in final solution
`= (235)/(700)xx100=33.57%`
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