20% aqueous `FeCl_(3)` solution has density of 1.1 gm/mL then molar concentration of this solution is ……….

Options

A. `0.028`
B. `1.357`
C. `0.163`
D. `1.47`

Answer

B

Explanation

`20% FeCl_(3)` solution means 20 gm `FeCl_(3)` is present in 100 gm of solution.
`therefore` Volume of 100 gm solution `= (100)/(1.1)=90.91` mL
Moles of 20 gm `FeCl_(3)` solution `= (20)/(162)=0.1234` mol
So, molar concentration solution
`= (0.1234xx1000)/(90.91)=1.357 M`