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25 mL Ba(OH)(2) solution is neutralized ...

25 mL `Ba(OH)_(2)` solution is neutralized by 35 mL 0.1 M HCl, what will be molarity of `Ba(OH)_(2)` solution ?

A

`0.14`

B

`0.28`

C

`0.35`

D

`0.07`

Text Solution

Verified by Experts

The correct Answer is:
D
`(M_(1)V_(1))/(1)=(M_(2)V_(2))/(2)`
`M_(1)xx25=(0.1xx35)/(2)=0.07`
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