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1.5 % Urea solution and 5.25% unknown su...

1.5 % Urea solution and 5.25% unknown substance's solutions are isotonic. The density of both the solutions are `1 gm//cm^(3)` then what is the molecular weight of unknown substance ?

A

104

B

210

C

88

D

120

Text Solution

Verified by Experts

The correct Answer is:
B
`C_(1)=C_(2)`
`therefore (1.5xx1000)/(100xx60)=(5.25xx1000)/(100xxM)`
`therefore M =210` g/mol.
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