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The freezing point of 0.01 M KCl solutio...

The freezing point of 0.01 M KCl solution is `-2^(@)C`. If `BaCl_(2)` is completely ionized, what is the freezing point of 0.01 M `BaCl_(2)` solution ?

A

`-3^(@)C`

B

`+3^(@)C`

C

`-2^(@)C`

D

`-4^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta T_(f)=K_(f)xx m xx i`
`2=K_(f)xx0.01xx2`
`K_(f)=100^(@)C"kg mol"^(-1)`
`Delta T_(f)=K_(f)xx m xx i`
`=100xx0.01xx3`
`= 3^(@)C`
`T_(f)=-3^(@)C`
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