The vapour pressure of water is 17.5 mm at `20^(@)C` temp. what is the vapour pressure of solution `20^(@)C` prepared by dissolving 18 gram glucose in to 178.2 gram water at `20^(@)C` temp. ?

Options

A. 17.675 mm
B. 15.750 mm
C. 16.500 mm
D. 17.325 mm

Answer

D

Explanation

`P_(1)^(0)=17.5 mm, P_(1)=?`
`(P_(1)^(@)-P_(1))/(P_(1)^(@))=(M_(1)w_(2))/(M_(2)w_(1))`
`(17.5-P_(1))/(17.5)=(18xx18)/(180xx178.2)`
`P_(1)=17.325 mm`