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The freezing point of the aqueous soluti...

The freezing point of the aqueous solution of urea is `-0.6^(@)C`. How much urea should be added to 3 kg water to get such solution ? `(K_(f)=1.5^(@)"C Kg. mol"^(-1))`

A

72 gram

B

6.0 gram

C

3.6 gram

D

2.4 gram

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta T = K_(f).m=K_(f)xx ((1000xx W)/(M xx W_(o)))`
`W=(Delta Txx M xx W_(o))/(K_(f)xx1000)`
`therefore W=(0.6xx60xx3000)/(1.5xx1000)=72` gram.
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