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H(3)C-underset(CH(3))underset("| ")("C ...

`H_(3)C-underset(CH_(3))underset("| ")("C ")H-CH=CH_(2)overset(HBr)rarr`

A

`CH_(3)-underset(CH_(3))underset("| ")("C ")H-underset("Br ")underset("| ")("C ")H-CH_(3)`

B

`CH_(3)-overset("Br ")overset("| ")underset(CH_(3))underset("| ")("C ")-CH_(2)-CH_(3)`

C

`CH_(3)-underset(CH_(3))underset("| ")("C ")H-CH_(2)CH_(2)Br`

D

`CH_(3)-overset("Br ")overset("| ")underset(CH_(3))underset("| ")("C ")-CH_(2)CH_(2)Br`

Text Solution

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The correct Answer is:
B
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