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The major product in the given reaction ...

The major product in the given reaction is …..
`CH_(3)-CH_(2)-underset("I")underset("|")("C")H-CH_(2)-CH_(3)overset(NaOH)underset(H_(2)O)rarr`

A

`CH_(3)-underset("OH ")underset("| ")("C ")H-CH_(2)-CH_(2)CH_(3)`

B

`CH_(3)-CH_(2)-underset("OH ")underset("| ")("C ")H-CH_(2)CH_(3)`

C

`CH_(3)-CH=CH-CH_(2)-CH_(3)`

D

`CH_(2)=CH-CH_(2)-CH_(2)CH_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
The reaction takes place by `S_(N)1` path.
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