An alkene ''A'' on reaction with `O_(3)` and `Zn-H_(2)O` gives propanone and ehanal in rquimolar ratio. Addition of HCl to alkene ''A'' gives ''B'' as the major product. The structure of product ''B'' is :

Options

A. `H_(3)C-underset("Cl ")underset("| ")("C "H)-overset(CH_(3))overset("| ")underset(CH_(3))underset("| ")("C ")H`
B. `Cl-CH_(2)-CH_(2)-overset(CH_(3))overset("| ")underset(CH_(3))underset("| ")("C ")H`
C. `H_(3)C-CH_(2)-overset(CH_(2)Cl)overset("| ")("C ")H-CH_(3)`
D. `H_(3)C-CH_(2)-overset(CH_(3))overset("| ")underset("Cl ")underset("| ")("C ")-CH_(3)`

Answer

D

Explanation