(3cos theta+cos3 theta)/(3sin theta-sin3 theta)=

(3 cos theta+cos 3 theta)/(3 sin theta-sin 3 theta)=

(cos theta+cos3 theta)/(sin theta-sin3 theta) is equal to:

(sin3 theta+cos3 theta)/(cos theta-sin theta)=1+2xx sin2 theta

Prove that (cos^3theta+sin^3 theta)/(cos theta+sin theta)+(cos^3 theta-sin^3 theta)/(cos theta-sin theta)=2

(cos4 theta+cos3 theta+cos2 theta)/(sin4 theta+sin3 theta+sin2 theta)=cot3 theta

Prove that : (cos4 theta+cos3 theta+cos2 theta)/(sin4 theta+sin3 theta+sin2 theta)=cot3 theta

If (sin theta + cos theta)/(sin theta - cos theta)=3 , then the value of sin^(4)theta - cos^(4)theta is:

(3 cos theta + cos 3 theta )/( 3 sin theta - sin 3 theta ) =

Use Binomial theorem and De Moivre's theorem to show cos 3 theta=4 cos^3 theta-3cos theta , sin3theta=3sin theta-4 sin^3 theta Express cos ntheta as sum of product of power of sin theta "and" cos theta . Do the same thing for sin n theta.

Prove that (cos^3 theta-sin^3 theta)/(cos theta-sin theta) = 1+cos theta sin theta