A point move in a straight line so that its distance from the start in t sec is equal to `s= (1)/(4) t^(4)- 4t^(3) + 16t^(2)`. What will be acceleration and at what times is its velocity equal to zero?

A point moves in a straight line so that its displacement x metre at a time t second is such that t=(x^2 −1) ^1/2 . Its acceleration in m/s^2 at time t second is:

A partical is moving in a straight line such that its displacement at any time t is given by s=4t^(3)+3t^(2) . Find the velocity and acceleration in terms of t.

A particle moves along a straight line such that its displacement at any time t is given by s = 3t^(3)+7t^(2)+14t + 5 . The acceleration of the particle at t = 1s is

A particle moves along a staight line such that its displacement at any time t is given by s=t^3-6t^2+3t+4m . Find the velocity when the acceleration is 0.

(a) If the initial velocity of a particle is u and collinear acceleration at any time t is at, calculate the velocity of the particle after time t . (b) A particle moves along a straight line such that its displacement at any time t is given by s = (t^(3) - 6 t^(2) + 3t + 4)m . What is the velocity of the particle when its acceleration is zero?

A particle is moving in a straight line such that its distance s at any time t is given by s=(t^(4))/(4)-2t^(3)+4t^(2)-7. Find when its velocity is maximum and acceleration minimum.

A body moves in a straight line along x-axis, its distance from the origin is given by the equation x = 8t-3t ^(2). The average velocity in the interval from t =0 to t =4 is

A particle is moving in a straight line. At time t, the distance between the particle from its starting point is given by x =t- 9t^(2) + t^(3) . lts acceleration will be zero at