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A point on the curve y= x^(3)-3x + 5 at ...

A point on the curve `y= x^(3)-3x + 5` at which the tangent line is parallel to `y= -2x` is

A

(1,3)

B

(0,5)

C

`((1)/(sqrt3), 5- (8 sqrt3)/(9))`

D

`((1)/(sqrt2), 0)`

Text Solution

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The correct Answer is:
To find the point on the curve \( y = x^3 - 3x + 5 \) where the tangent line is parallel to the line \( y = -2x \), we need to follow these steps: ### Step 1: Find the derivative of the curve The derivative \( \frac{dy}{dx} \) gives us the slope of the tangent line at any point on the curve. Given: \[ y = x^3 - 3x + 5 \] Differentiating with respect to \( x \): \[ \frac{dy}{dx} = 3x^2 - 3 \] ### Step 2: Set the derivative equal to the slope of the given line Since the tangent line is parallel to \( y = -2x \), the slope of the tangent line must be \( -2 \). Therefore, we set the derivative equal to \( -2 \): \[ 3x^2 - 3 = -2 \] ### Step 3: Solve for \( x \) Rearranging the equation: \[ 3x^2 - 3 + 2 = 0 \] \[ 3x^2 - 1 = 0 \] \[ 3x^2 = 1 \] \[ x^2 = \frac{1}{3} \] \[ x = \pm \frac{1}{\sqrt{3}} \quad \text{(or } x = \pm \frac{\sqrt{3}}{3} \text{)} \] ### Step 4: Find the corresponding \( y \) values Now we will find the \( y \) values for both \( x = \frac{1}{\sqrt{3}} \) and \( x = -\frac{1}{\sqrt{3}} \). **For \( x = \frac{1}{\sqrt{3}} \)**: \[ y = \left(\frac{1}{\sqrt{3}}\right)^3 - 3\left(\frac{1}{\sqrt{3}}\right) + 5 \] \[ = \frac{1}{3\sqrt{3}} - \frac{3\sqrt{3}}{3} + 5 \] \[ = \frac{1}{3\sqrt{3}} - \sqrt{3} + 5 \] \[ = 5 - \sqrt{3} + \frac{1}{3\sqrt{3}} \] To simplify, we can write: \[ = 5 - \frac{3\sqrt{3}}{3} + \frac{1}{3\sqrt{3}} = 5 - \frac{8\sqrt{3}}{3} \] **For \( x = -\frac{1}{\sqrt{3}} \)**: \[ y = \left(-\frac{1}{\sqrt{3}}\right)^3 - 3\left(-\frac{1}{\sqrt{3}}\right) + 5 \] \[ = -\frac{1}{3\sqrt{3}} + \sqrt{3} + 5 \] \[ = 5 + \sqrt{3} - \frac{1}{3\sqrt{3}} \] \[ = 5 + \frac{3\sqrt{3}}{3} - \frac{1}{3\sqrt{3}} = 5 + \frac{8\sqrt{3}}{3} \] ### Step 5: Write the points Thus, the points on the curve where the tangent line is parallel to \( y = -2x \) are: 1. \( \left(\frac{1}{\sqrt{3}}, 5 - \frac{8\sqrt{3}}{3}\right) \) 2. \( \left(-\frac{1}{\sqrt{3}}, 5 + \frac{8\sqrt{3}}{3}\right) \)
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