If the primitive of (1)/(e^(x)-1)^(2) is...

If the primitive of `(1)/(e^(x)-1)^(2)` is `f(x) - log |g (x)| + C` then

dom f = R

`g (x) = 1 - e^(x)`

`domf=~{0}`

`f(x) = 1 - e^(-x)`

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