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Coordinates of the vertices B and C of t...

Coordinates of the vertices B and C of the base of a triangle ABC are `(-a,0)` and (a, 0) respectively. If `C-B=pi//3`, the vertex A lies on the curve

A

`x^(2)-y^(2)+2sqrt(3)xy-a^(2)=0`

B

`x^(2)+y^(2)+2sqrt(3)xy-a^(2)=0`

C

`sqrt(3)(x^(2)-y^(2))+2xy-sqrt(3)a^(2)=0`

D

`sqrt(3)(x^(2)+y^(2))-2xy+sqrt(3)a^(2)=0`

Text Solution

Verified by Experts

The correct Answer is:
C
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