A ray of light along x+sqrt(3)y=sqrt(...

A ray of light along `x+sqrt(3)y=sqrt(3)` gets reflected upon reaching x-axis, the equation of the reflected rays is (1) `sqrt(3)y=x-sqrt(3)` (2) `y=sqrt(3)x-sqrt(3)` (3) `sqrt(3)y=x-1` (4) `y=x+sqrt(3)`

`sqrt(3)y=x-sqrt(3)`

`y=sqrt(3)x-sqrt(3)`

`sqrt(3)y=x-1`

`y=x+sqrt(3)`

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A ray of light along x+sqrt(3)y=sqrt(3) gets reflected upon reaching x-axis,the equation of the reflected ray is

A ray of light along x+sqrt(3)y=sqrt(3) gets reflected upon reaching x-axis,the equation of the reflected ray is: a.y=x+sqrt(3)b .sqrt(3)y=x-sqrt(3)c*y=sqrt(3)x-sqrt(3)dsqrt(3)y=x-1

sqrt(2)x+sqrt(3)y=0 sqrt(3)x+sqrt(8)y=0

Direct tangents are : (A) y=sqrt(3)x+sqrt(3),y=-sqrt(3)x+sqrt(3)

sqrt(2)x+sqrt(3)y=0sqrt(3)x-sqrt(8)y=0

sqrt (2x) -sqrt (3y) = 0sqrt (3x) -sqrt (3y) = 0

(2)/(sqrt(3)+sqrt(5))+(5)/(sqrt(3)-sqrt(5))=x sqrt(3)+y sqrt(5)

A beam of light is sent along the line x-y=1 , which after refracting from the x-axis enters the opposite side by turning through 30^0 towards the normal at the point of incidence on the x-axis. Then the equation of the refracted ray is (a) (2-sqrt(3))x-y=2+sqrt(3) (b) (2+sqrt(3))x-y=2+sqrt(3) (c) (2-sqrt(3))x+y=(2+sqrt(3)) (d) y=(2-sqrt(3))(x-1)

Evaluate : ( sqrt(2)x + sqrt(3)y ) ( sqrt(2)x + sqrt(3)y )

MCGROW HILL PUBLICATION-CARTESIAN SYSTEM OF RECTANGULAR COORDINATES AND STRAIGHT LINES -QUESTIONS FROM PREVIOUS YEARS. (AIEEE/JEE MAIN PAPERS)

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